2x^2+12x-2160=0

Solution for 2x^2+12x-2160=0 equation:

2x^2+12x-2160=0

a = 2; b = 12; c = -2160;
Δ = b2-4ac
Δ = 122-4·2·(-2160)
Δ = 17424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{17424}=132$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-132}{2*2}=\frac{-144}{4}
=-36
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+132}{2*2}=\frac{120}{4}
=30
$